Question

A graph of $x$ versus $t$ is shown in figure. Choose correct alternatives from below.

• A. The particle was released from rest at $t=0$
• B. At $B$, the acceleration $a>0$
• C. At $C$, the velocity and the acceleration vanish
• D. The speed at $D$ exceeds that at $E$

Answer 1

Answer: (A), (C), (D)

From graph, when $t=0$, the particle is released from rest at $A$, hence, $v=0$.
At $B$, the graph is parallel to time axis, hence velocity is constant there. Thus acceleration a is zero.
At $C$, the graph changes slope, where velocity and acceleration vanish.
Average velocity for motion between $A$ and $D$ is negative because the value of $x$ is decreasing with time $t$. The slope of graph (which represents speed) is more at $D$ than at $E$. Therefore speed at $D$ is more than that at $F$