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Q.
A graph of $x$ versus $t$ is shown in figure. Choose correct alternatives from below.
Motion in a Straight Line
Solution:
From graph, when $t=0$, the particle is released from rest at $A$, hence, $v=0$.
At $B$, the graph is parallel to time axis, hence velocity is constant there. Thus acceleration a is zero.
At $C$, the graph changes slope, where velocity and acceleration vanish.
Average velocity for motion between $A$ and $D$ is negative because the value of $x$ is decreasing with time $t$. The slope of graph (which represents speed) is more at $D$ than at $E$. Therefore speed at $D$ is more than that at $F$
