A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio (CP/CV) of the mixture is

Question

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio (CP/CV) of the mixture is (A) 1.4 (B) 1.54 (C) 1.59 (D) 1.62

Tardigrade Admin · Accepted Answer

μ 1=(16/4)=4 μ 2=(16/32)=(1/2) (CP)m i x=((μ )1 CP1 + (μ )2 CP2/(μ )1 + (μ )2) (CV)m i x=((μ )1 CV1 + (μ )2 CV2/(μ )1 + (μ )2) (&gamma; )m i x=((CP)m i x/(CV)m i x)

Q. A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio CV​CP​​ of the mixture is

1.4

1.54

1.59

1.62

μ1​=416​=4 μ2​=3216​=21​ (CP​)mix​=(μ)1​+(μ)2​(μ)1​CP1​​+(μ)2​CP2​​​ (CV​)mix​=(μ)1​+(μ)2​(μ)1​CV1​​+(μ)2​CV2​​​ (γ)mix​=(CV​)mix​(CP​)mix​​

Q. A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio $\frac{C _{P}}{C _{V}}$ of the mixture is