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  4. A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio (CP/CV) of the mixture is

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Q. A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio $\frac{C_{P}}{C_{V}}$ of the mixture is

NTA AbhyasNTA Abhyas 2022

Solution:

$\mu _{1}=\frac{16}{4}=4$
$\mu _{2}=\frac{16}{32}=\frac{1}{2}$
$\left(C_{P}\right)_{m i x}=\frac{\left(\mu \right)_{1} C_{P_{1}} + \left(\mu \right)_{2} C_{P_{2}}}{\left(\mu \right)_{1} + \left(\mu \right)_{2}}$
$\left(C_{V}\right)_{m i x}=\frac{\left(\mu \right)_{1} C_{V_{1}} + \left(\mu \right)_{2} C_{V_{2}}}{\left(\mu \right)_{1} + \left(\mu \right)_{2}}$
$\left(\gamma \right)_{m i x}=\frac{\left(C_{P}\right)_{m i x}}{\left(C_{V}\right)_{m i x}}$