A gas is a mixture of two parts by volume of hydrogen and one part by volume nitrogen. If the velocity of sound in hydrogen at 27° C is given as 1330 m / s, find the ratio of velocity of sound in hydrogen at 27° C to the gaseous mixture at 127° C.

Question

A gas is a mixture of two parts by volume of hydrogen and one part by volume nitrogen. If the velocity of sound in hydrogen at 27° C is given as 1330 m / s, find the ratio of velocity of sound in hydrogen at 27° C to the gaseous mixture at 127° C. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

v text sound propto √(T/M) M text mix =(2 × 2+28/3)=(32/3) ∴ (v text sound / H 2/v text sound / text mix )=√(300 × 32/2 × 400 × 3)=2

Q. A gas is a mixture of two parts by volume of hydrogen and one part by volume nitrogen. If the velocity of sound in hydrogen at $2 7^{\circ} C$ is given as $1330 m / s$ , find the ratio of velocity of sound in hydrogen at $2 7^{\circ} C$ to the gaseous mixture at $12 7^{\circ} C$ .

$v_{sound} \propto \frac{T}{M}$
$M_{mix} = \frac{2 \times 2 + 28}{3} = \frac{32}{3}$
$∴ \frac{v _{sound / H_{2}}}{v _{sound / mix}} = \frac{300 \times 32}{2 \times 400 \times 3} = 2$

Q. A gas is a mixture of two parts by volume of hydrogen and one part by volume nitrogen. If the velocity of sound in hydrogen at 27∘C is given as 1330m/s, find the ratio of velocity of sound in hydrogen at 27∘C to the gaseous mixture at 127∘C.

vsound ​∝MT​​ Mmix ​=32×2+28​=332​ ∴vsound / mix ​vsound /H2​​​=2×400×3300×32​​=2

Q. A gas is a mixture of two parts by volume of hydrogen and one part by volume nitrogen. If the velocity of sound in hydrogen at $2 7^{\circ} C$ is given as $1330 m / s$ , find the ratio of velocity of sound in hydrogen at $2 7^{\circ} C$ to the gaseous mixture at $12 7^{\circ} C$ .

$v_{sound} \propto \frac{T}{M}$
$M_{mix} = \frac{2 \times 2 + 28}{3} = \frac{32}{3}$
$∴ \frac{v _{sound / H_{2}}}{v _{sound / mix}} = \frac{300 \times 32}{2 \times 400 \times 3} = 2$