Question

A gas has a vapour density $11.2$. The volume occupied by $1g$ of gas at NTP is

• A. 1 L
• B. 11.2 L
• C. 22.4 L
• D. unpredictable

Answer 1

Answer: (A)

1. Molecular weight
$=2\times$ vapour density
2. Volume of $1$ mole of gas at NTP $=22.4L$
Vapour density of gas $=11.2$
Hence, molecular weight $=2\times 11.2$
$=22.4g$
$\because$ The volume of $22.4g$ gas at NTP
$=22.4L$
$\therefore$ The volume of $1g$ gas at NTP
$=\frac{22.4}{22.4}\times 1=1L$