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  4. A gas has a vapour density 11.2. The volume occupied by 1 g of gas at NTP is

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Q. A gas has a vapour density $11.2$. The volume occupied by $1\, g$ of gas at NTP is

AMUAMU 2005

Solution:

1. Molecular weight
$=2 \times$ vapour density
2. Volume of $1$ mole of gas at NTP $=22.4\, L$
Vapour density of gas $=11.2$
Hence, molecular weight $=2 \times 11.2$
$=22.4\, g$
$\because$ The volume of $22.4\, g$ gas at NTP
$=22.4\, L$
$\therefore $ The volume of $1\, g$ gas at NTP
$=\frac{22.4}{22.4} \times 1=1 \,L$