A gas cylinder containing cooking gas can withstand a pressure at 14.9 atm. The pressure gauge of the cylinder indicates 12 atm. at 27° C . Due to a sudden fire in the building its temperature starts rising. At what temperature will the cylinder explode?

Question

A gas cylinder containing cooking gas can withstand a pressure at 14.9 atm. The pressure gauge of the cylinder indicates 12 atm. at 27° C . Due to a sudden fire in the building its temperature starts rising. At what temperature will the cylinder explode? (A) 372.5 K (B) 3.725 K (C) 37.25 K (D) None of these

Tardigrade Admin · Accepted Answer

textT = 273 + 27 = 300 textK (P1/T1)=(P2/T2) Since volume of the cylinder is constant T2=(T1 P2/P1)=(300 × 14.9/12) =372.5 K

Q. A gas cylinder containing cooking gas can withstand a pressure at 14.9 atm. The pressure gauge of the cylinder indicates 12 atm. at $2 7^{\circ} C$ . Due to a sudden fire in the building its temperature starts rising. At what temperature will the cylinder explode?

372.5 K

3.725 K

37.25 K

None of these

$T = 273 + 27 = 300 K$

$\frac{P _{1}}{T _{1}} = \frac{P _{2}}{T _{2}}$

Since volume of the cylinder is constant

$T_{2} = \frac{T _{1} P _{2}}{P _{1}} = \frac{300 \times 14.9}{12}$

$= 372.5 K$

Q. A gas cylinder containing cooking gas can withstand a pressure at 14.9 atm. The pressure gauge of the cylinder indicates 12 atm. at 27∘C . Due to a sudden fire in the building its temperature starts rising. At what temperature will the cylinder explode?