A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at:

Question

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at: (A) 518 nm (B) 1035 nm (C) 325 nm (D) 743 nm

Tardigrade Admin · Accepted Answer

(1/λ) = (1/λ1) + (1/λ2) (1/355) = (1/680) + (1/λ2) (1/λ2) = (680 - 355/355 × 680) ⇒ λ2 =743 nm

Q. A gas absorbs a photon of $355 nm$ and emits at two wavelengths. If one of the emissions is at $680 nm$ , the other is at:

$518 nm$

$1035 nm$

$325 nm$

$743 nm$

$\frac{1}{λ} = \frac{1}{λ _{1}} + \frac{1}{λ _{2}}$

$\frac{1}{355} = \frac{1}{680} + \frac{1}{λ _{2}}$

$\frac{1}{λ _{2}} = \frac{680 - 355}{355 \times 680}$

$\Rightarrow λ_{2} = 743 nm$

Q. A gas absorbs a photon of 355nm and emits at two wavelengths. If one of the emissions is at 680nm, the other is at:

518nm

1035nm

325nm

743nm