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Chemistry
A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at:
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Q. A gas absorbs a photon of $355 nm$ and emits at two wavelengths. If one of the emissions is at $680 nm$, the other is at:
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A
$518 nm$
B
$1035 nm$
C
$325 nm$
D
$743 nm$
Solution:
$\frac{1}{\lambda} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}$
$\frac{1}{355} = \frac{1}{680} + \frac{1}{\lambda_{2}}$
$\frac{1}{\lambda_{2}} = \frac{680 - 355}{355 \times 680}$
$\Rightarrow \lambda_{2} =743 nm$