A galvanometer of resistance 50 Ω is converted into an ammeter by connecting a low resistance (shunt) of value 1 Ω in parallel to the galvanometer, S . If full-scale deflection current of the galvanometer is 10 mA , then the maximum current that can be measured by the ammeter is -

Question

A galvanometer of resistance 50 Ω is converted into an ammeter by connecting a low resistance (shunt) of value 1 Ω in parallel to the galvanometer, S . If full-scale deflection current of the galvanometer is 10 mA , then the maximum current that can be measured by the ammeter is - (A) 500 mA (B) 510 mA (C) 610 mA (D) 490 mA

Tardigrade Admin · Accepted Answer

S=G(Ig/I - Ig) Shunt and Galvnometer are in parallel combination <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-c24iqi0iy9n8.png" /> 1=50× (10/I - 10) I-10=500 I=510 mA

Q. A galvanometer of resistance $50 Ω$ is converted into an ammeter by connecting a low resistance (shunt) of value $1 Ω$ in parallel to the galvanometer, $S$ . If full-scale deflection current of the galvanometer is $10 m A$ , then the maximum current that can be measured by the ammeter is -

$500 m A$

$510 m A$

$610 m A$

$490 m A$

$S = G \frac{I _{g}}{I - I _{g}}$
Shunt and Galvnometer are in parallel combination

$1 = 50 \times \frac{10}{I - 10}$
$I - 10 = 500$
$I = 510 m A$

Q. A galvanometer of resistance 50Ω is converted into an ammeter by connecting a low resistance (shunt) of value 1Ω in parallel to the galvanometer, S . If full-scale deflection current of the galvanometer is 10mA , then the maximum current that can be measured by the ammeter is -

500mA

510mA

610mA

490mA