Question

A galvanometer of resistance $50 \, \Omega $ is converted into an ammeter by connecting a low resistance (shunt) of value $1 \, \Omega $ in parallel to the galvanometer, $S$ . If full-scale deflection current of the galvanometer is $10 \, mA$ , then the maximum current that can be measured by the ammeter is -

• A. $500 \, mA$
• B. $510 \, mA$
• C. $610 \, mA$
• D. $490 \, mA$

Answer 1

Answer: (B)

$S=G\frac{I_{g}}{I - I_{g}}$
Shunt and Galvnometer are in parallel combination

$1=50\times \frac{10}{I - 10}$
$I-10=500$
$I=510 \, mA$