A galvanometer of resistance 50 Ω gives a full scale deflection for a current 5×10-4. The resistance that The resistance that should be connected in series with the galvanometer to read 3 V is

Question

A galvanometer of resistance 50 Ω gives a full scale deflection for a current 5×10-4. The resistance that The resistance that should be connected in series with the galvanometer to read 3 V is (A) 595 Ω (B) 5050 Ω (C) 5059 Ω (D) 5950 Ω

Tardigrade Admin · Accepted Answer

Given, G=50 Ω Ig =5 × 10-4 A V =3 V We know that, net resistance, R=(V/Ig)-G R=(3/5 × 10-4)-50 R=6000-50 R=5950 Ω

Q. A galvanometer of resistance $50 Ω$ gives a full scale deflection for a current $5 \times 1 0^{- 4}$ . The resistance that The resistance that should be connected in series with the galvanometer to read $3 V$ is

$595 Ω$

$5050 Ω$

$5059 Ω$

$5950 Ω$

Given, $G = 50 Ω$
$I_{g} = 5 \times 1 0^{- 4} A$
$V = 3 V$
We know that, net resistance,
$R = \frac{V}{I _{g}} - G$
$R = \frac{3}{5 \times 1 0 ^{- 4}} - 50$
$R = 6000 - 50$
$R = 5950 Ω$

Q. A galvanometer of resistance 50Ω gives a full scale deflection for a current 5×10−4. The resistance that The resistance that should be connected in series with the galvanometer to read 3V is

595Ω

5050Ω

5059Ω

5950Ω