Question

A galvanometer of resistance $50\, \Omega$ gives a full scale deflection for a current $5\times10^{-4}$. The resistance that The resistance that should be connected in series with the galvanometer to read $3 \,V$ is

• A. $595 \, \Omega$
• B. $5050 \, \Omega$
• C. $5059 \, \Omega$
• D. $5950 \, \Omega$

Answer 1

Answer: (D)

Given, $G=50 \,\Omega$
$I_{g} =5 \times 10^{-4}\, A $
$V =3 V$
We know that, net resistance,
$R=\frac{V}{I_{g}}-G $
$R=\frac{3}{5 \times 10^{-4}}-50 $
$R=6000-50$
$R=5950\, \Omega$