A galvanometer of resistance 20 Ω is to be converted into an ammeter of range 1 A. If a current of 1 mA produces full scale deflection, the shunt required for the purpose is

Question

A galvanometer of resistance 20 Ω is to be converted into an ammeter of range 1 A. If a current of 1 mA produces full scale deflection, the shunt required for the purpose is (A) 0.01 Ω (B) 0.05 Ω (C) 0.02 Ω (D) 0.04 Ω

Tardigrade Admin · Accepted Answer

S=(Ig G/I-Ig)=(10-3 × 20/1-1 × 10-3)=0.02 ω

Q. A galvanometer of resistance $20 Ω$ is to be converted into an ammeter of range $1 A$ . If $a$ current of $1 m A$ produces full scale deflection, the shunt required for the purpose is

$0.01 Ω$

$0.05 Ω$

$0.02 Ω$

$0.04 Ω$

$S = \frac{I _{g} G}{I - I _{g}} = \frac{1 0 ^{- 3} \times 20}{1 - 1 \times 1 0 ^{- 3}} = 0.02 ω$

Q. A galvanometer of resistance 20Ω is to be converted into an ammeter of range 1A. If a current of 1mA produces full scale deflection, the shunt required for the purpose is

0.01Ω

0.05Ω

0.02Ω

0.04Ω