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Q. A galvanometer of resistance $20 \, \Omega$ is to be converted into an ammeter of range $1 \,A$. If $a$ current of $1 mA$ produces full scale deflection, the shunt required for the purpose is

ManipalManipal 2018

Solution:

$S=\frac{I_{g} G}{I-I_{g}}=\frac{10^{-3} \times 20}{1-1 \times 10^{-3}}=0.02 \omega$