A force of 49 newton is just able to move a block of wood weighting 10 kg on a rough horizontal surface- Its coefficient of friction is:

Question

A force of 49 newton is just able to move a block of wood weighting 10 kg on a rough horizontal surface- Its coefficient of friction is: (A) 1 (B) 0.7 (C) 0.5 (D) zero

Tardigrade Admin · Accepted Answer

Coefficient of friction μ =(F/R) =(F/mg) =(49/10× 10) =0.49 ≈ 0.5

Q. A force of 49 newton is just able to move a block of wood weighting 10 kg on a rough horizontal surface- Its coefficient of friction is:

1

0.7

0.5

zero

Coefficient of friction $μ = \frac{F}{R}$ $= \frac{F}{m g}$ $= \frac{49}{10 \times 10}$ $= 0.49$ $\approx 0.5$

Q. A force of 49 newton is just able to move a block of wood weighting 10 kg on a rough horizontal surface- Its coefficient of friction is:

1

0.7

0.5

zero

Coefficient of friction μ=RF​ =mgF​ =10×1049​ =0.49 ≈0.5

Coefficient of friction $μ = \frac{F}{R}$ $= \frac{F}{m g}$ $= \frac{49}{10 \times 10}$ $= 0.49$ $\approx 0.5$