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Q. A force of 49 newton is just able to move a block of wood weighting 10 kg on a rough horizontal surface- Its coefficient of friction is:

MGIMS WardhaMGIMS Wardha 2005

Solution:

Coefficient of friction $ \mu =\frac{F}{R} $ $ =\frac{F}{mg} $ $ =\frac{49}{10\times 10} $ $ =0.49 $ $ \approx 0.5 $