A force of 10 N acts on a body of mass 20 kg for 10 seconds. The change in its momentum is:

Question

A force of 10 N acts on a body of mass 20 kg for 10 seconds. The change in its momentum is: (A) 50 kg-m/s (B) 100 kg-m/s (C) 300 kg-m/s (D) 1000 kg-m/s

Tardigrade Admin · Accepted Answer

Given: F=10 N , m=20 kg Δ t=10 sec The change in momentum of the body is given by Δ p =F × Δ t=10 × 10 =100 kg - m / s

Q. A force of $10 N$ acts on a body of mass $20 k g$ for $10$ seconds. The change in its momentum is:

50 kg-m/s

100 kg-m/s

300 kg-m/s

1000 kg-m/s

Given : $F = 10 N, m = 20 k g$
$Δ t = 10 sec$
The change in momentum of the body is given by
$Δ p = F \times Δ t = 10 \times 10$
$= 100 k g - m / s$

Q. A force of 10N acts on a body of mass 20kg for 10 seconds. The change in its momentum is: