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  4. A force of 10 N acts on a body of mass 20 kg for 10 seconds. The change in its momentum is:

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Q. A force of $10 \,N$ acts on a body of mass $20 \,kg$ for $10$ seconds. The change in its momentum is:

ManipalManipal 2004Laws of Motion

Solution:

Given : $F=10 \,N , m=20\, kg$
$\Delta t=10\, sec$
The change in momentum of the body is given by
$\Delta p =F \times \Delta t=10 \times 10 $
$=100 \,kg - m / s$