A flow of 106 electrons per second in a conducting wire constitutes a flow of current of

Question

A flow of 106 electrons per second in a conducting wire constitutes a flow of current of (A) 1.6 × 10-15 A (B) 1.6 × 10-11 A (C) 1.6 × 10-12 A (D) 1.6 × 10-19 A

Tardigrade Admin · Accepted Answer

Given, n=106 electron per second We know that, q= ne q=106 × 1.6 × 10-19 C Now, as the flow charge is 1.6 × 10-13 coulomb per second So, i=1.6 × 10-13 A

Q. A flow of $1 0^{6}$ electrons per second in a conducting wire constitutes a flow of current of

$1.6 \times 1 0^{- 15} A$

$1.6 \times 1 0^{- 11} A$

$1.6 \times 1 0^{- 12} A$

$1.6 \times 1 0^{- 19} A$

$1.6 \times 1 0^{- 13} A$

Given, $n = 1 0^{6}$ electron per second
We know that, $q =$ ne
$q = 1 0^{6} \times 1.6 \times 1 0^{- 19} C$
Now, as the flow charge is
$1.6 \times 1 0^{- 13}$ coulomb per second
So, $i = 1.6 \times 1 0^{- 13} A$

Q. A flow of 106 electrons per second in a conducting wire constitutes a flow of current of

1.6×10−15A

1.6×10−11A

1.6×10−12A

1.6×10−19A

1.6×10−13A

Given, n=106 electron per second We know that, q= ne q=106×1.6×10−19C Now, as the flow charge is 1.6×10−13 coulomb per second So, i=1.6×10−13A