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Physics
A flow of 106 electrons per second in a conducting wire constitutes a flow of current of
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Q. A flow of $10^6$ electrons per second in a conducting wire constitutes a flow of current of
KEAM
KEAM 2015
Current Electricity
A
$1.6 \times 10^{-15} A$
4%
B
$1.6 \times 10^{-11} A$
3%
C
$1.6 \times 10^{-12} A$
14%
D
$1.6 \times 10^{-19} A$
8%
E
$1.6 \times 10^{-13} A$
8%
Solution:
Given, $n=10^{6}$ electron per second
We know that, $q=$ ne
$q=10^{6} \times 1.6 \times 10^{-19} C$
Now, as the flow charge is
$1.6 \times 10^{-13}$ coulomb per second
So, $i=1.6 \times 10^{-13} A$