A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is θ. What is the tension of the chain at the end point?

Question

A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is θ. What is the tension of the chain at the end point? (A) (W/2) operatornamecosec θ (B) (W/2) sec θ (C) W cos θ (D) ( W /3) sec θ

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2462982e4a8e4137f00264a5d2fdd704-.png" /> 2 T sin θ= W ⇒ T =( W /2 sin θ)=( W /2) operatornamecosec θ

Q. A flexible chain of weight W hangs between two fixed points $A$ and $B$ at the same level. The inclination of the chain with the horizontal at the two points of support is $θ$ . What is the tension of the chain at the end point?

$\frac{W}{2} cosec θ$

$\frac{W}{2} sec θ$

$W cos θ$

$\frac{W}{3} sec θ$

$2 T sin θ = W$
$\Rightarrow T = \frac{W}{2 s i n θ} = \frac{W}{2} cosec θ$

Q. A flexible chain of weight W hangs between two fixed points A and B at the same level. The inclination of the chain with the horizontal at the two points of support is θ. What is the tension of the chain at the end point?

2W​cosecθ

2W​secθ

Wcosθ

3W​secθ