Question

A flexible chain of weight W hangs between two fixed points $A$ and $B$ at the same level. The inclination of the chain with the horizontal at the two points of support is $\theta$. What is the tension of the chain at the end point?

• A. $\frac{W}{2} \operatorname{cosec} \theta$
• B. $\frac{W}{2} \sec \theta$
• C. $W \cos \theta$
• D. $\frac{ W }{3} \sec \theta$

Answer 1

Answer: (A)

$2 T \sin \theta= W $
$\Rightarrow T =\frac{ W }{2 \sin \theta}=\frac{ W }{2} \operatorname{cosec} \theta$