A flask of capacity 2 L is heated from 35°C to 45°C. What volume of air will escape from the flask?

Question

A flask of capacity 2 L is heated from 35°C to 45°C. What volume of air will escape from the flask? (A) 10 mL (B) 20 mL (C) 60 mL (D) 50 mL

Tardigrade Admin · Accepted Answer

(V1/T1) =(V2/T2) V1 =2L, T1 =35+273=308 K V2=?, T2 =45+273 =318 K V2 =(2/308)×318=2.06 L Capacity of flask = 2 L Volume of air escaped=2.06-2=0.06 L or 60 mL

Q. A flask of capacity $2 L$ is heated from $3 5^{\circ} C$ to $4 5^{\circ} C$ . What volume of air will escape from the flask?

$10 m L$

$20 m L$

$60 m L$

$50 m L$

$\frac{V _{1}}{T _{1}}$ $= \frac{V _{2}}{T _{2}}$
$V_{1}$ $= 2 L$ , $T_{1}$ $= 35 + 273 = 308 K$
$V_{2} = ?$ , $T_{2}$ $= 45 + 273$ $= 318 K$
$V_{2}$ $= \frac{2}{308} \times 318 = 2.06 L$
Capacity of flask = $2 L$
Volume of air escaped= $2.06 - 2 = 0.06 L$ or $60 m L$

Q. A flask of capacity 2L is heated from 35∘C to 45∘C. What volume of air will escape from the flask?

10mL

20mL

60mL

50mL