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Q. A flask of capacity $2\, L$ is heated from $ 35^{\circ}C$ to $45^{\circ}C$. What volume of air will escape from the flask?

States of Matter

Solution:

$ \frac{V_{1}}{T_{1}}$ $=\frac{V_{2}}{T_{2}}$
$V_{1}$ $=2L$, $T_{1}$ $=35+273=308 \,K$
$V_{2}=?$, $T_{2}$ $=45+273$ $=318\, K$
$V_{2}$ $=\frac{2}{308}\times318=2.06\, L$
Capacity of flask = $2\, L$
Volume of air escaped=$2.06-2=0.06 L$ or $60 \, mL$