A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12 cm below the surface, the radius of this circle (in cm) is

Question

A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12 cm below the surface, the radius of this circle (in cm) is (A) 36 √5 (B) 4 √5 (C) 36 √7 (D) 36 / √7

Tardigrade Admin · Accepted Answer

sin i c =(1/μ)=( r /√ r 2+ h 2) Using h =12 cm , μ=4 / 3 We get r =(36/√7) cm .

Q. A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $4/3$ and the fish is $12 c m$ below the surface, the radius of this circle (in cm) is

$365$

$45$

$367$

$36/ 7$

$sin i_{c} = \frac{1}{μ} = \frac{r}{r ^{2} + h ^{2}}$
Using $h = 12 c m,$
$μ = 4/3$
We get $r = \frac{36}{7} c m .$

Q. A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface, the radius of this circle (in cm) is

365​

45​

367​

36/7​