Q. A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $4/3$ and the fish is $12 \,cm$ below the surface, the radius of this circle (in cm) is
VITEEEVITEEE 2016
Solution:
$\sin i _{ c }=\frac{1}{\mu}=\frac{ r }{\sqrt{ r ^{2}+ h ^{2}}}$
Using $h =12\, cm , $
$\mu=4 / 3$
We get $r =\frac{36}{\sqrt{7}}\, cm .$