A cylinder of fixed capacity 44.8 litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by 15 °C ? (R = 8.31 J mol-1 K-1)

Question

A cylinder of fixed capacity 44.8 litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by 15 °C ? (R = 8.31 J mol-1 K-1) (A) 265 J (B) 310.10 J (C) 373.95 J (D) 387.97 J

Tardigrade Admin · Accepted Answer

Since one mole of any ideal gas at STP occupies a volume of 22.4 litre. Therefore, cylinder of fixed capacity 44.8 litre must contain 2 moles of helium at STP. For helium, CV = (3/2) R (monatomic) ∴ Heat needed to raise the temperature, Q = number of moles × molar specific heat × raise in temperature = 2 × (3/2) R × 15 = 45R = 45× 8.31 J = 373.95 J

Q. A cylinder of fixed capacity $44.8$ litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by $15^{\circ} C$ ?
$(R = 8.31 J m o l^{- 1} K^{- 1})$

$265 J$

$310.10 J$

$373.95 J$

$387.97 J$

Q. A cylinder of fixed capacity 44.8 litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by 15∘C ? (R=8.31Jmol−1K−1)

265J

310.10J

373.95J

387.97J

Q. A cylinder of fixed capacity $44.8$ litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by $15^{\circ} C$ ?
$(R = 8.31 J m o l^{- 1} K^{- 1})$

$265 J$

$310.10 J$

$373.95 J$

$387.97 J$