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Q. A cylinder of fixed capacity $44.8$ litres contains helium gas at standard temperature and pressure. What is the amount of heat needed to raise the temperature of the gas in the cylinder by $15\,{}^{\circ}C$ ?
$(R = 8.31\, J \,mol^{-1}\, K^{-1})$

Kinetic Theory

Solution:

Since one mole of any ideal gas at $STP$ occupies a volume of $22.4$ litre.
Therefore, cylinder of fixed capacity $44.8$ litre must contain $2$ moles of helium at $STP$.
For helium, $C_{V} = \frac{3}{2} R$ (monatomic)
$\therefore \quad$ Heat needed to raise the temperature,
$Q =$ number of moles $\times$ molar specific heat $\times$ raise in temperature
$= 2 \times \frac{3}{2} R \times 15 = 45R = 45\times 8.31\,J = 373.95\,J$