A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 s. Its average velocity is

Question

A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 s. Its average velocity is (A) zero (B) 4π m s-1 (C) 2π m s-1 (D) 8π m s-1

Tardigrade Admin · Accepted Answer

Average velocity =( textDisplacement/ textTime taken) =(2R/t)=(2×40/40)=2 m s-1

Q. A cyclist moving on a circular track of radius $40 m$ completes half a revolution in $40 s$ . Its average velocity is

zero

$4 π m s^{- 1}$

$2 π m s^{- 1}$

$8 π m s^{- 1}$

Average velocity $= \frac{Displacement}{Time taken}$
$= \frac{2 R}{t} = \frac{2 \times 40}{40} = 2 m s^{- 1}$

Q. A cyclist moving on a circular track of radius 40m completes half a revolution in 40s. Its average velocity is

zero

4πms−1

2πms−1

8πms−1

Average velocity =Time takenDisplacement​ =t2R​=402×40​=2ms−1

Q. A cyclist moving on a circular track of radius $40 m$ completes half a revolution in $40 s$ . Its average velocity is

$4 π m s^{- 1}$

$2 π m s^{- 1}$

$8 π m s^{- 1}$

Average velocity $= \frac{Displacement}{Time taken}$
$= \frac{2 R}{t} = \frac{2 \times 40}{40} = 2 m s^{- 1}$