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Physics
A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 s. Its average velocity is
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Q. A cyclist moving on a circular track of radius $40\, m$ completes half a revolution in $40 \,s$. Its average velocity is
Motion in a Straight Line
A
zero
13%
B
$4\pi \,m\,s^{-1}$
7%
C
$2\pi \,m\,s^{-1}$
76%
D
$8\pi \,m\,s^{-1}$
5%
Solution:
Average velocity $=\frac{\text{Displacement}}{\text{Time taken}}$
$=\frac{2R}{t}=\frac{2\times40}{40}=2\,m\,s^{-1}$