A cyclist moves in a circular track or radius 100 m . If the coefficient of friction 0.2 . Then the maximum speed with which the cyclist can take a turn without leaving inwards, is

Question

A cyclist moves in a circular track or radius 100 m . If the coefficient of friction 0.2 . Then the maximum speed with which the cyclist can take a turn without leaving inwards, is (A) 14.0 m/s (B) 140 m/s (C) 1.4 m/s (D) 9.8 m/s

Tardigrade Admin · Accepted Answer

Given μ =0.2, g=9.8 m / s 2 r =100 m Maximum velocity with which the cyclist can take a circular path of radius r is v=√μ r g So, v=√0.2 × 100 × 9.8 =√196=14 m / s

Q. A cyclist moves in a circular track or radius $100 m$ . If the coefficient of friction $0.2$ . Then the maximum speed with which the cyclist can take a turn without leaving inwards, is

14.0 m/s

140 m/s

1.4 m/s

9.8 m/s

Given $μ = 0.2, g = 9.8 m / s^{2}$
$r = 100 m$
Maximum velocity with which the cyclist can take a circular path of radius $r$ is $v = μ r g$
So, $v = 0.2 \times 100 \times 9.8$
$= 196 = 14 m / s$

Q. A cyclist moves in a circular track or radius 100m . If the coefficient of friction 0.2 . Then the maximum speed with which the cyclist can take a turn without leaving inwards, is