A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is

Question

A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-2zq93vjpxkeq.png" /> (A) 160 J (B) 150 J (C) 600 J (D) 900 J

Tardigrade Admin · Accepted Answer

Work done during cyclic process ABCDA = area enclosed by ABCDA = (( textAB + textCD/2)) × textAD = ((2 + 1)/2) × 1 02 = 1 text. 5 × 1 02 textJ = 150 J <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-2zq93vjpiszi.png" />

Q. A cyclic process is shown in the figure. Work done during the cyclic process $A BC D A$ is

160 J

150 J

600 J

900 J

Work done during cyclic process ABCDA
= area enclosed by ABCDA
$= (\frac{AB + CD}{2}) \times AD$
$= \frac{( 2 + 1 )}{2} \times 1 0^{2}$
$= 1.5 \times 1 0^{2} J$
= 150 J

Q. A cyclic process is shown in the figure. Work done during the cyclic process ABCDA is