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Q. A cyclic process is shown in the figure. Work done during the cyclic process $ABCDA$ is

Question

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Work done during cyclic process ABCDA
= area enclosed by ABCDA
$= \left(\frac{\text{AB} + \text{CD}}{2}\right) \times \text{AD}$
$= \frac{\left(2 + 1\right)}{2} \times 1 0^{2}$
$= 1 \text{.} 5 \times 1 0^{2} \text{J}$
= 150 J

Solution