A current strength of 9.65 A is passed through excess fused AICI3 for 5 h How many litres of chlorine will be liberated at STP ? (F = 96500 C)

Question

A current strength of 9.65 A is passed through excess fused AICI3 for 5 h How many litres of chlorine will be liberated at STP ? (F = 96500 C) (A) 2.016 (B) 1.008 (C) 11.2 (D) 20.16

Tardigrade Admin · Accepted Answer

From Faraday first law of electrolysis w=zit z=( text Atomic mass / text electrons exchanged × 96500) Cl - longrightarrow (1/2) Cl 2+1 e- w=(35.5 × 9.65 × 5 × 60 × 60/1 × 96500) =63.9 g ∵ At STP, 71 g Cl 2 has volume =22.4 L ∴ At STP , 63.9 g Cl 2 will have volume =(22.4 × 63.9/71)=20.16 L

Q. A current strength of $9.65 A$ is passed through excess fused $A I C I_{3}$ for 5 h How many litres of chlorine will be liberated at $STP$ ? $(F = 96500 C)$

$2.016$

$1.008$

$11.2$

$20.16$

$10.08$

Q. A current strength of 9.65A is passed through excess fused AICI3​ for 5 h How many litres of chlorine will be liberated at STP ? (F=96500C)

2.016

1.008

11.2

20.16

10.08