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  4. A current strength of 9.65 A is passed through excess fused AICI3 for 5 h How many litres of chlorine will be liberated at STP ? (F = 96500 C)

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Q. A current strength of $9.65\, A$ is passed through excess fused $AICI_3$ for 5 h How many litres of chlorine will be liberated at $STP$ ? $(F = 96500 \,C)$

KEAMKEAM 2013Electrochemistry

Solution:

From Faraday first law of electrolysis

$w=zit $

$z=\frac{\text { Atomic mass }}{\text { electrons exchanged } \times 96500} $

$Cl ^{-} \longrightarrow \frac{1}{2} Cl _{2}+1 e^{-} $

$w=\frac{35.5 \times 9.65 \times 5 \times 60 \times 60}{1 \times 96500} $

$=63.9 \,g$

$\because$ At STP, $71 \,g \,Cl _{2}$ has volume $=22.4\, L$

$\therefore $ At $STP , 63.9 \,g \,Cl _{2}$ will have volume

$=\frac{22.4 \times 63.9}{71}=20.16\, L$