A current strength of 0.965 amperes is passed through excess fused AlCl3 for 5 hours. How many litres of chlorine will be liberated at STP? (F = 96500 C)

Question

A current strength of 0.965 amperes is passed through excess fused AlCl3 for 5 hours. How many litres of chlorine will be liberated at STP? (F = 96500 C) (A) 2.016 (B) 1.008 (C) 11.2 (D) 20.16

Tardigrade Admin · Accepted Answer

1 textF arrow 11.2 text L Cl text2 text at STP ∴ No.of Faradays=(0 . 965 × 5 × 60 × 60/96500)=0.18 ∴ textVolume textof Cl text2 text at STP=0.18× 11.2 textL text= text2.016 textL

Q. A current strength of $0.965$ amperes is passed through excess fused $A lC l_{3}$ for $5$ hours. How many litres of chlorine will be liberated at STP? $(F = 96500 C)$

2.016

1.008

11.2

20.16

$1 F \to 11.2 L Cl_{2} at STP$
$∴ N o . o f F a r a d a ys = \frac{0.965 \times 5 \times 60 \times 60}{96500} = 0.18$
$∴ Volume of Cl_{2} at STP = 0.18 \times 11.2 L$
$= 2.016 L$

Q. A current strength of 0.965 amperes is passed through excess fused AlCl3​ for 5 hours. How many litres of chlorine will be liberated at STP? (F=96500C)