Question

A current strength of $0.965$ amperes is passed through excess fused $AlCl_{3}$ for $5$ hours. How many litres of chlorine will be liberated at STP? $\left(F = 96500 \, C\right)$

• A. 2.016
• B. 1.008
• C. 11.2
• D. 20.16

Answer 1

Answer: (A)

$1 \, \text{F} \rightarrow 11.2 \text{ L Cl}_{\text{2}} \text{ at STP}$
$\therefore No.of \, Faradays=\frac{0 . 965 \times 5 \times 60 \times 60}{96500}=0.18$
$\therefore \text{Volume} \, \text{of Cl}_{\text{2}}\text{ at STP}=0.18\times 11.2 \, \text{L}$
$\text{=} \, \text{2.016} \, \text{L}$