A current of 4.8 A is flowing in a conductor. The number of electrons passing per sec through the conductor will be

Question

A current of 4.8 A is flowing in a conductor. The number of electrons passing per sec through the conductor will be (A) 3 × 1019 (B) 76.8 × 1020 (C) 7.68 × 1020 (D) 3 × 1020

Tardigrade Admin · Accepted Answer

Current I=( textCharge (Q)/ texttime (t)) I=(ne/t) or (n/t)=(I/e)=((4.8 A)/(1.6×10-9 C)) =3×1019 / sec

Q. A current of $4.8 A$ is flowing in a conductor. The number of electrons passing per sec through the conductor will be

$3 \times 1 0^{19}$

$76.8 \times 1 0^{20}$

$7.68 \times 1 0^{20}$

$3 \times 1 0^{20}$

Current $I = \frac{Charge (Q)}{time (t)}$
$I = \frac{n e}{t}$
or $\frac{n}{t} = \frac{I}{e} = \frac{( 4.8 A )}{( 1.6 \times 1 0 ^{- 9} C )}$
$= 3 \times 1 0^{19} / sec$

Q. A current of 4.8A is flowing in a conductor. The number of electrons passing per sec through the conductor will be

3×1019

76.8×1020

7.68×1020

3×1020