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  4. A current of 4.8 A is flowing in a conductor. The number of electrons passing per sec through the conductor will be

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Q. A current of $4.8\, A$ is flowing in a conductor. The number of electrons passing per sec through the conductor will be

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Solution:

Current $I=\frac{\text{Charge (Q)}}{\text{time (t)}}$
$I=\frac{ne}{t} $
or $\frac{n}{t}=\frac{I}{e}=\frac{\left(4.8 A\right)}{\left(1.6\times10^{-9} C\right)}$
$=3\times10^{19} / sec$