A cube of side b has charge q at each of its vertice The electric field at the centre of the cube will be

Question

A cube of side b has charge q at each of its vertice The electric field at the centre of the cube will be (A) (q/b2) (B) (q/2 b2) (C) (32 q/b2) (D) zero

Tardigrade Admin · Accepted Answer

The symmetry indicates, the resultant electric field will be 0. The charges sitting at either end of each of the body diagonals will cancel each others’ electric field.

Q. A cube of side $b$ has charge $q$ at each of its vertice The electric field at the centre of the cube will be

$\frac{q}{b ^{2}}$

$\frac{q}{2 b ^{2}}$

$\frac{32 q}{b ^{2}}$

zero

The symmetry indicates, the resultant electric field will be $0.$ The charges sitting at either end of each of the body diagonals will cancel each others’ electric field.

Q. A cube of side b has charge q at each of its vertice The electric field at the centre of the cube will be

b2q​

2b2q​

b232q​