Question

A cube of side $b$ has charge $q$ at each of its vertice The electric field at the centre of the cube will be

• A. $\frac{q}{b^{2}}$
• B. $\frac{q}{2 b^{2}}$
• C. $\frac{32 q}{b^{2}}$
• D. zero

Answer 1

Answer: (D)

The symmetry indicates, the resultant electric field will be $0. $ The charges sitting at either end of each of the body diagonals will cancel each others’ electric field.