Question

A critical angle for a medium is $60^{\circ }.$ Then the refractive index of the medium will be

• A. $\sqrt{3}$
• B. $\frac{\sqrt{3}}{2}$
• C. $\frac{2}{\sqrt{3}}$
• D. $\frac{1}{\sqrt{3}}$

Answer 1

Answer: (C)

$\mu =\frac{1}{\sin C}$
or $\mu =\frac{1}{\sin 60^{\circ }}=\frac{1}{\sqrt{3}/2}=\frac{2}{\sqrt{3}}$