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Q. A critical angle for a medium is $60^\circ.$ Then the refractive index of the medium will be

Gujarat CETGujarat CET 2006Ray Optics and Optical Instruments

Solution:

$ \mu = \frac{1}{\sin\, C}$
or $ \mu = \frac{1}{\sin\, 60^\circ}=\frac{1}{\sqrt 3/2 }=\frac{2}{\sqrt 3}$