A cooking gas contains carbon and hydrogen only. A volume of 11.2 L of this gas is found to weigh 22 g at STP. Then the molecular formula of the gas is

Question

A cooking gas contains carbon and hydrogen only. A volume of 11.2 L of this gas is found to weigh 22 g at STP. Then the molecular formula of the gas is (A) C 3 H 8 (B) C 2 H 2 (C) C 2 H 4 (D) C 2 H 6

Tardigrade Admin · Accepted Answer

Volume of 11.2 L of gas arrow 22 g at S T P Volume of 22.4 L of gas arrow 44 g ∴ The mass of C 3 H 8 is 44 g. Hence, cooking gas contains propane (C3 H8)

Q. A cooking gas contains carbon and hydrogen only. A volume of $11.2 L$ of this gas is found to weigh $22 g$ at STP. Then the molecular formula of the gas is

$C_{3} H_{8}$

$C_{2} H_{2}$

$C_{2} H_{4}$

$C_{2} H_{6}$

$C_{3} H_{4}$

Volume of $11.2 L$ of gas $\to 22 g$ at $STP$
Volume of $22.4 L$ of gas $\to 44 g$
$∴$ The mass of $C_{3} H_{8}$ is $44 g$ .
Hence, cooking gas contains propane $(C_{3} H_{8})$

Q. A cooking gas contains carbon and hydrogen only. A volume of 11.2L of this gas is found to weigh 22g at STP. Then the molecular formula of the gas is

C3​H8​

C2​H2​

C2​H4​

C2​H6​

C3​H4​

Volume of 11.2L of gas →22g at STP Volume of 22.4L of gas →44g ∴ The mass of C3​H8​ is 44g. Hence, cooking gas contains propane (C3​H8​)