Question

A convex polygon has 101 sides. Number of different diagonals which it can have, is

• A. 4850
• B. 4949
• C. 5151
• D. 5050

Answer 1

Answer: (B)

Use number of diagonals $=\frac{n(n-3)}{2}=\frac{101\cdot 98}{2}=101\cdot 49=4949$