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  4. A convex polygon has 101 sides. Number of different diagonals which it can have, is

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Q. A convex polygon has 101 sides. Number of different diagonals which it can have, is

Permutations and Combinations

Solution:

Use number of diagonals $=\frac{ n ( n -3)}{2}=\frac{101 \cdot 98}{2}=101 \cdot 49=4949$