A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1 m from it. The image is formed at a distance of :

Question

A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1 m from it. The image is formed at a distance of : (A)  (18/3) m behind the mirror (B)  (18/3) m infront of the mirror (C)  (4/9) m behind the mirror (D) ? (4/9) m in front of the mirror

Tardigrade Admin · Accepted Answer

Given, f =(1.6/2)=0.8 m and u =-1 m beginarrayl (1/ f )=(1/ v )-(1/ u ) (1/ v )=(1/0.8)-(1/-1)=(10/8)+1=(9/4) ⇒ v =(4/9) m endarray

Q. A convex mirror of radius of curvature $1.6 m$ has an object placed at a distance of $1 m$ from it. The image is formed at a distance of :

$\frac{18}{3}$ m behind the mirror

$\frac{18}{3}$ m infront of the mirror

$\frac{4}{9}$ m behind the mirror

? $\frac{4}{9}$ m in front of the mirror

Given, $f = \frac{1.6}{2} = 0.8 m$ and $u = - 1 m$
$< b r / > < b r / > \frac{1}{f} = \frac{1}{v} - \frac{1}{u} < b r / > \frac{1}{v} = \frac{1}{0.8} - \frac{1}{- 1} = \frac{10}{8} + 1 = \frac{9}{4} < b r / >\Rightarrow v = \frac{4}{9} m < b r / > < b r / >$

Q. A convex mirror of radius of curvature 1.6m has an object placed at a distance of 1m from it. The image is formed at a distance of :

318​ m behind the mirror

318​ m infront of the mirror

94​ m behind the mirror

? 94​ m in front of the mirror