Question

A convex mirror of radius of curvature $1.6\, m$ has an object placed at a distance of $1\,m$ from it. The image is formed at a distance of :

• A. $ \frac{18}{3} $ m behind the mirror
• B. $ \frac{18}{3} $ m infront of the mirror
• C. $ \frac{4}{9} $ m behind the mirror
• D. ? $ \frac{4}{9} $ m in front of the mirror

Answer 1

Answer: (C)

Given, $f =\frac{1.6}{2}=0.8 m$ and $u =-1 m$
$
\begin{array}{l}
\frac{1}{ f }=\frac{1}{ v }-\frac{1}{ u } \\
\frac{1}{ v }=\frac{1}{0.8}-\frac{1}{-1}=\frac{10}{8}+1=\frac{9}{4} \\
\Rightarrow v =\frac{4}{9} m
\end{array}
$